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Brewhouse Efficiency Calculation w/Multiple Malts

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  • Brewhouse Efficiency Calculation w/Multiple Malts

    So we are running some numbers by hand and have a question on Brewhouse Efficiency calculations...

    Calculating our Extract Efficiency (Extract Yield) isn't an issue:
    Extract Eff. = (volume of wort x weight/volume x SG x °P%) / grain weight

    I have Brewhouse Eff. as,
    Brewhouse Eff. = Extract Eff. / cg 'as-is'

    Where cg 'as-is' = (%extract cgdb x (1-%moisture))

    Calculating the Brewhouse efficiency isn't a problem with a single malt beer, but how does one calculate it with a wort which has multiple malts? If the additional malts were just a small percentage of the total malt bill, I'd just ignore them but if they are significant how do you account for them in the denominator of the equation?

    To put it another way, how do you include the %extract for each malt used in the above equation?

    Much appreciate the help!

    Cheers.

  • #2
    This calculation looks like it is the formula for % Utilization rather than % Efficiency.

    Calculating Utilization is much more useful than Efficiency in daily brewhouse reports, but calculating Efficiency based on the average Utilization for a specific grain bill will help reduce waste and fine tune things from a bean counter stand point.

    I will need a beer or three to go deeper into this.
    Todd G Hicks
    BeerDenizen Brewing Services

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    • #3
      Oh yea, the answer.

      Use weighted averages to calculate the efficiency per each grain. There will be some lab work to do on each grain, or you can use the specs from your maltster.

      Need more beer to get into this any deeper. Any beer math gurus out there want to take over.
      Todd G Hicks
      BeerDenizen Brewing Services

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      • #4
        Perhaps even easier, just use a weighted average of each grains CG 'As-Is'.

        Cheers!

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