Calculating Hydrostatic Pressure

[Sam_Pecoraro]

Can anyone explain to me how to calculate hydrostatic pressure at the bottom of a conical in psi? A rule of thumb would even help. Thanks

[CaptainEBC]

p = ρ * g * h

p = hydrostatic pressure [bar]

ρ = specific gravity of the liquid [kg/m³]

g = acceleration due to gravity [m/s²]

h = height of the liquid column [m]

[Sam_Pecoraro]

Thanks for the response Chris. I saw that equation and then posted here because I didn't think I knew how to convert that to useful terms in the brewery. I think I almost have it though:

p = 1 bar = 14.05 psi
ρ = SG = liquid kg/m3 / water kg/m3, so SG *1000 = kg/m3
gravity = 9.8 m/s2
h = m

p = ρ * g * h

bar = 1055 kg/m3 * 9.8 m/s2 * 2 m

bar / 14.05 = psi = 1,471.7 ?????

Where am I going wrong?

[Sam_Pecoraro]

Here we go:

The unit for p is pascal.

1 pascal = 0.000145038 psi

Therefore, 2 meter high liquid at 1.055 SG above a conical will have...

pascals = 1055 kg/m3 * 9.8 m/s2 * 2 m

20,678 * 0.000145038 = 2.99 psi

So, correct me if I'm wrong, but to roughly figure out psi at the bottom of a conical:

PSI = (SG * 1,000) (9.8) (meters of liquid) (.000145038)

[Sam_Pecoraro]

Easiest:

PSI = SG * 1.42 * m

[lhall]

about 0.5 psi per foot