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Mash tun size/O.G. formula

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  • Mash tun size/O.G. formula

    Hello everyone,

    Looking for some help with finding a good formula for calculating the following:

    Brewing 10bbl batches, what is the highest O.G. beer that can be mashed in a 300 gallon total volume mash tun and not have the mash tun overflow. Mashing in with 1.5qts water/lb of grain.

    Thank you for your assistance!
    Last edited by Catfish002; 02-27-2017, 02:43 PM.

  • #2
    Beersmith.

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    • #3



      Sent from my iPhone using Tapatalk

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      • #4
        Thank you!

        Originally posted by dmartin View Post
        https://www.rackers.org/calcs.shtml


        Sent from my iPhone using Tapatalk
        Very helpful calculators. Thank you so much!

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        • #5
          Plenty of software (including free website calculators of varying accuracy) to calculate how much total volume you'd need for a certain mash size, but the OG will depend largely on your brewhouse efficiency - and to a lesser extent on the type of grain used.

          A tun with 300-gallon useful mash capacity should accommodate about 650 pounds of grain at 1.5 quarts/pound.

          https://www.rackers.org/calcs.shtml (see the "can I mash it?" section)

          The calculation itself, as far as I know, goes something like this:
          [mash water in gallons] + ([pounds of grain] * .08) = Gallons Total Mash Volume

          So for this example of 650 lb grain @ 1.5 qt/lb:
          650 * 1.5 = 975 quarts mash water...
          975 / 4 = 243.75 gallons mash water...
          (243.75) + (650 * .08) = 295.75 Gallons Total Mash Volume

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          • #6
            Thank you

            Originally posted by Yellowbeard View Post
            Plenty of software (including free website calculators of varying accuracy) to calculate how much total volume you'd need for a certain mash size, but the OG will depend largely on your brewhouse efficiency - and to a lesser extent on the type of grain used.

            A tun with 300-gallon useful mash capacity should accommodate about 650 pounds of grain at 1.5 quarts/pound.

            https://www.rackers.org/calcs.shtml (see the "can I mash it?" section)

            The calculation itself, as far as I know, goes something like this:
            [mash water in gallons] + ([pounds of grain] * .08) = Gallons Total Mash Volume

            So for this example of 650 lb grain @ 1.5 qt/lb:
            650 * 1.5 = 975 quarts mash water...
            975 / 4 = 243.75 gallons mash water...
            (243.75) + (650 * .08) = 295.75 Gallons Total Mash Volume
            Thank you. Very helpful info!

            Comment

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