Attn. all math geeks
Can somebody please check my math, here. I'm working with a new kind of product, and my figures don't seem 100% accurate. Solve for x:
A train leaving Michigan is travelling south at 72 MPH....Oops, sorry, wrong problem. Here it goes:
The fruit = 11.234 # per gallon @ 70 Brix
10 gallons will be added to 7.5 Bbls of beer.
Q) 10 gallons of fruit will increase 7.5 Bbls of beer (x) degrees plato.
A) Assuming that 1# of sugar raises 1 gallon of water 1.046, I came up with
2.3 degrees plato.
Am I close?
11.234 # per gal X 10 gal X .7 = 78.6 # of extract you're adding
78.6 lbs / 7.5 bbl = 10.5 lbs. extract per bbl
Using my handy Siebel Brew Computer (everyone should own one of these, they're only a few bucks),
12 deg. P wort has 32.4 lbs. extract per bbl.
if you add 10.5 lbs. extract per bbl,
42.9 lbs/bbl equals about 15.65 deg. P.
So in this example, it added 3.65 deg. P.
I didn't account for the volume increase (almost a half bbl) of the 10 gallons, but you get the idea.
Actually, you should account for the volume increase because it is significant.
So, given 7.5 bbl wort at 12 deg P,
you have 7.5 x 32.4 lbs/bbl = 243 lbs. total extract before fruit addition;
add 78.6 lbs. extract from the fruit gives you 321.6 lbs. total extract.
7.5 bbls plus 10 gallons gives you 7.823 bbls.
321.6 / 7.823 is 41.1 lbs. extract per bbl.
Back to the Siebel Brew Computer, 41.1 lbs/bbl equals a shade over 15 deg. P.
So in this more precise example, it raised the gravity about 3.0 deg. P.